Gravitational acceleration: g = _____ m/s 2 ... We can use this formula to determine the mass of Jupiter from the orbits of its four Galilean moons. ... What is earths acceleration due to gravity. That's why you would weigh 28 times your earth-weight on the sun (if you could survive! For example, an object falling near the surface of Jupiter will accelerate toward the Jupiter's surface at roughly 25.9 meters per second squared. You are right - gravity does change across the surface of the Earth and throughout its atmosphere, due to several effects. The period of a simple pendulum is given by the formula . The uniform acceleration produced in a freely falling object due to the gravitational pull of the earth is known as acceleration Due to Gravity. The gravitational acceleration on the sun is different from the gravitational acceleration on the earth and moon. Let's choose the Sun - it weighs 1.989×10 30 kg, approximately the same as 330,000 Earths. Free fall acceleration, also known as gravitational acceleration, differs for planets and astronomical bodies and is affected by their mass. The formula – G Mm(1/r 2 – 1/r 1 ) is more/less accurate than the formula mg(r 2 – r 1 ) for the difference of potential energy between two points r 2 and r 1 distance away from the centre of the earth. Other ways to compare space objects - Distance from the sun - rotation period The value of 'g' is different at different places on Earth. Follow the below tutorial which guides on how to calculate acceleration due to gravity. Another, common, gravity formula is the one you learned in school: the acceleration due to the gravity of the Earth, on a test mass. Measuring Acceleration due to Gravity: The Period of a Pendulum. Where on the formula does the space object you want to compare other space objects to go. For example, the acceleration due to gravity would be different on the Moon as compared to the one here on Earth. Introduction to Newton's law of gravitation. The acceleration of free fall is; when the Body falls due to earth’s gravitational pull, its velocity changes and is said to be accelerated due to .the earth’s gravity and it falls freely called as free fall. We will apply it to each moon separately. we then plug this into the force formula. (Neglect changes in … As we go deep into the Earth or higher from the Earth's surface, the value of g decreases. Knowing the mass of the earth, we can now get the acceleration of gravity as a function of distance from the center of the earth: g = Gmearth/r2. Homework Statement A simple pendulum and a mass-spring system have the same oscillation frequency f at the surface of the Earth. a g = g = acceleration of gravity (9.81 m/s 2, 32.17405 ft/s 2) The force caused by gravity - a g - is called weight. Find out the mass of the second object. • 697 N • 626 N • 628 N • 564 N A tank has the shape of an inverted circular cone with height 16m and base radius 3m. The Moon’s orbit has a radius of about 384,000 km (239,000 miles; approximately 60 Earth radii), and its period is 27.3 days (its synodic period, or period measured in terms of lunar phases, is about 29.5 days).Newton found the Moon’s inward acceleration in its orbit to be 0.0027 metre per second per second, the same as (1/60) 2 of the acceleration of a falling object at the surface of Earth. The gravitational pull of Jupiter is greater than the gravitational pull of Earth. This calculates the mass of the object. where, G - Gravitational constant (6.67*10-11 Newton-meter 2 / kg 2) M - mass of the planet or object on which you calculate surf. You can enter this large number into the calculator by typing 5.972e24. This point lies between the bodies on the line joining them at a position such that the products of the distance to each body with the mass of each body are equal. For example, you can compare one planet to another, based on their respective masses and radii. For example, the gravity of the Sun is almost 28 times that of the Earth, of Jupiter — about 2.6 times greater, and of Neptune — … Free PDF download for Acceleration Due To Gravity Calculator to score more marks in exams, prepared by expert Subject teachers from the latest edition of CBSE/NCERT books, Calculators – Math, Physics, Chemistry and Basic Calculator . To sort this out, it first helps to know a little Physics 101. ... What are Jupiter, Saturn, Uranus and Neptune composed of. Ans: The mass of the Jupiter is 319 times more than that of the earth but its gravity is only 2.5 times more than that of the earth because the weight of a body on a planet is the product of the mass of the body and acceleration due to the gravity of the planet. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. Calculate the period of oscillations according to the formula above: T = 2π√(L/g) = 2π * √(2/9.80665) = 2.837 s . Gravity is the attraction mass has for mass. When in orbit, some 200 km above Earth’s surface, the force of gravity on the shuttle is 1. nearly as much. F=ma = .5 x 50 = 25 N. 2) It's weight in newtons is the force of gravity on the squid. Gravitation (part 2) Current time:0:00Total duration:10:41. Find out the mass of the first object. Solve it once the easy way, using Gauss's law for gravity. Earth would be accelerating towards Jupiter at about 20.9 m/s^2, and people on the near side would feel acceleration of 24.8 towards Jupiter, but relative to Earth that's only 3.9 m/s^2, so not enough to overcome Earth's gravity of -9.8 m/s^2. g = Acceleration due to gravity on the surface of the Earth. The acceleration due to gravity at the surface of the planet = 7.35 m/s 2. As an equation this is: ( Where: g = gravity field of a body (acceleration due to gravity in ms-2) r = distance from centre of the body (in m) Task 1 Acceleration due to gravity on the sun is about 274.0 m/s 2, or about 28 times the acceleration that it is here on earth. The Acceleration due to Gravity calculator computes the acceleration due to gravity based on the Universal Gravity Constant, the mass of the object (M) and the distance from the center of mass of the object (r).. Suppose that the Earth was an infinite flat slab of thickness t with the same mean density as the Earth. It is convenient when solving Atwood's machine problems. Jupiter is known to have 2.5 times the gravity of earth where earth has approximated gravity of 9.8 m/s 2, Jupiter has an approximated gravity of 24.79 m/s 2. This means that an object falling under the influence of gravity will fall faster by 9.8 meters per second each second. So 2.53 x 9.8 m/s^s = 24.8 m/s^2. When […] Jupiter; Mass (kg) 1.8986E+27: Mean Radius (km) 69911: m (mass relative to Earth) 317.832: r (mean radius relative to Earth) 10.973: g-force: 2.639: Acceleration (m/s/s) 25.885: Gravity Solutions. And, Acceleration due to gravity ,g = ? The formula –G Mm(1/r2– 1/r1) is more/less accurate than the formula mg(r2– r1) for the difference of potential energy between two points r2and r1distance away from the centre of the earth. But, at large distances from the Earth, or around other planets or moons, it is varying. Multiplying g by the mass of a person gives the weight W of the person. (r) This is the distance to the center of mass of the object. The relationship between the acceleration and the force is F =ma. ANS) As we find out value of g by two methods. Describe other ways you could investigate the acceleration of objects due to gravity.-Formula? To expand a little bit on Ian’s answer, I think it is important for you to understand the manner in which we come about this 9.81 [math]\frac{\text{m}}{\text{s}^2} [/math] acceleration that we experience on the earth’s surface. The acceleration due to gravity is different based on the mass of the star, planet, moon or asteroid and the distance from its center of mass and its surface. The mass of a 10 kg dumbell will be larger on the earth. Gravitic acceleration = Gm/r the place G is the gravitational consistent G = 9.8 m is the mass (which might proceed to be comparable) r is the radius of earth a million.8 as a effect. Use the fact that a Neutron Star has about 1.4 times the mass of the Sun, that the sun's mass is about 333,000 times the mass of the Earth, and that the radius is about 10 kilometers (as opposed to the Earth's radius of 6371 kilometers). (b) Acceleration due to gravity at depth d … Acceleration due to gravity is not the same on all planets. A spacecraft of mass 6000 kg lifts off the surface of Jupiter, where the acceleration due to gravity is 25 Newtons per kilogram (25 meters per second - 20738323 An object on Jupiter's surface is 10 times farther from Jupiter's center than it would be if on Earth's surface. The acceleration due to gravity, … Ignore any centrifugal effects and state your answer using the given symbols only. so if R differences to a bigger quantity, your velocity decreases whilst in comparison with the unique radius. W = mg (6) The acceleration due to gravity in space is zero, which is … Moon has 1/6th of Earth's gravity . ). Solve for acceleration of gravity: physical pendulum Solve for period. Acceleration due to gravity is independent of mass of the earth/mass of the body. The same person, will weigh much more on Jupiter, than on Earth. the Force of gravity is 10 times larger on B • But F = ma or acceleration = Force/mass so the acceleration due to gravity is G m Earth / r2 Earth • Does not depend on mass so all objects have same acceleration (ala Galileo). Obtain a formula to evaluate the acceleration due to gravity at A. This means that the centripetal acceleration at the Equator is about 0.03 m/s 2 (metres per second squared). Thus, acceleration due to gravity is defined as the acceleration produced on a freely falling body due to the gravity of the earth. Effective gravity on the equator is reduced by the rotation, but only by about 1/3 of a percent The bulge of the Earth's equator Assuming the Earth is exactly spherical, we expect gravity to … Let's choose Earth - its mass is equal to 5.972×10 24 kg. Mass and distance affect gravity.as mass increases, gravity increases. To calculate time we to use the following formula: •It is not universal. g = G × (M / R 2). Using this formula for when m2 is a planet (such as earth) we get. gravity of moon is 1/6 earth gravity F = mg where g is acceleration due to gravity g = 9.8 m/s^2. But for calculating value of g at height or depth, following expressions are used: If the acceleration due to gravity on the surface of the earth is 9.8 m/s 2, what will be the acceleration due to gravity on the surface of a planet whose mass and radius both are two times the … 1 Newton in Earth gravity is the equivalent weight of 1/9.80665 kg on Earth. When we rearrange the equation and plug all the numbers in, we find that the mass of … Free Fall Acceleration. The value of this acceleration for any planet is known as g. Just as the gravity of a planet is uniform, so is the value of g for that planet. Compare this value to the accepted acceleration due to gravity value (9.8 m/s 2). The formula to calculate the final velocity of an object in free fall is: v = v₀ + g * t . You can even define direction of acceleration to be upward for one body and downward for a second body, if this is convenient. The above term is called the acceleration due to gravity. In other words: any object co-rotating with the Earth at the equator has its measured weight reduced by 0.34 percent, thanks to the Earth's rotation. We will use the Earthly figure of 9.80665 m/s², but feel free to check how the pendulum would behave on other planets. (c) Acceleration due to gravity is independent of the mass of the Earth/mass of the body. In physics, gravitational acceleration is the acceleration of an object in free fall within a vacuum (and thus without experiencing drag).This is the steady gain in speed caused exclusively by the force of gravitational attraction. The discovery of jupiter's galilen moons with his telescope, those moons and venus phases supported the sun is the center of our solar system. accelerate at the same rate. T = 2π √ [L/g] Or g = 4 π^2 [L/T^2] By accurately measuring L and T, g is calculated. ? Using physics, you can compare the acceleration due to gravity of two different revolving objects. According to the universal law of gravitation, f = GmM/(r+h) 2. The force on different bodies will be different but the acceleration will be the same. If the arm is 5.25m long and pivots about one end, at what angular speed (in rpm) should it spin so that the acceleration of the lander is the same as the acceleration due to gravity at the surface of Europa? Note that for a given mass, as R gets smaller, V will get larger. Solve for center of mass or moment of inertia. Answer questions. Acceleration due to gravity. Acceleration due to gravity at the space station. The mass of a 10 kg dumbell will be different on the moon. (Updated for 2021-2022) Board Exams Score high with CoolGyan and secure top rank in your exams. Compare this to the acceleration due to gravity which is about 9.8 m/s 2 and you can see how tiny an effect this is - you would weigh about 0.3% less at the equator than at the poles! Does depend on mass, radius of Earth • G is universal constant The ratio of forces is: The acceleration due to gravity g is never constant. Thus, the acceleration due to gravity on Jupiter surface is 2.66 times more than that of Earth’s surface. What is the apple's acceleration (Newton's 2nd Law of Motion): a apple = F/M apple = GM earth /R earth 2 = 9.8 meters/sec 2 Note that the mass of the apple (M apple) had divided out of the equation. Formula of Acceleration due to Gravity. The equation is derived from Newton's second law and Newton's Law of universal gravitation. Jupiter is the biggest planet, in the solar system. The weight of an object is the force on the object due to gravity. Free online physics calculators, mechanics, energy, calculators. Space station speed in orbit. By definition, when at rest on the surface of the earth, the weight ,W, of the object is the repulsive force in the equation F = ma, and a = g, the acceleration due to gravity. Calculate the acceleration due to gravity when the spacecraft is 160,000 meters above the planet and compare this to the acceleration due to gravity near the surface of the planet. 10 m/s2. The default value is set to 9.80665 ms-2 which is the standard acceleration due to earths gravity. If the acceleration due to gravity on the surface of the earth is 9.8 m/s 2, what will be the acceleration due to gravity on the surface of a planet whose mass and radius both are two times the … Answer: (a) decreases (b) decreases (c) mass of the body This is derived using Newton's second law f=ma and assuming Earth gravity of 9.80665 m/s2. You can calculate the acceleration due to gravity at the surface of a planet using the formula: 8= GM R? Now, Mass of object (m) = 25 kg Acceleration due to gravity (g) = 9.77 m/s 2 Weight of object (w) = ? We know that the acceleration due to gravity is equal to 9.8 m/s2, the Gravitational constant (G) is 6.673 × 10−11 Nm2/kg2, the radius of the Earth is 6.37 × 106 m, and mass cancels out. It has a value of 9.81 m/s 2 on the surface of the Earth. The value of 9.80665 m/s 2 with six significant digits is the so called standard acceleration due to gravity or standard gravity. Acceleration due to gravity on the sun is about 274.0 m/s 2, or about 28 times the acceleration that it is here on earth. Let us verify this value by plugging the Earth's … Practice questions Researchers at NASA load a 100-kilogram package onto a rocket on Earth. Question 11. Therefore, the acceleration due to gravity (g) is given by = GM/r 2. Being that it takes the weight of an object on earth and converts it to the weight on Planets, the formula is Weight on Planets= (Weight on Earth/9.81m/s 2) * gravitational force of the planet. Where, Suppose there existed a planet that went around the sun twice as fast as the earth. The escape velocity formula is applied in finding the escape velocity of any body or any planet if mass and radius are known. So the 300-fold increase in force (due to the greater mass) must be divided by 100 since the separation distance is 10 times greater. You can also enter acceleration due to the pull of gravity for other places in the solar system such as Mars ( 3.71 ms -2 ), Moon ( 1.62 ms -2 ), Titan ( 1.35 ms -2 ) or Europa ( 1.31 ms -2 ) for example. The formula to find a planet’s acceleration due to gravity (g) is as follows: g = GM r2 where G is the gravitational constant, M is the mass of the planet, and r is the planet’s radius. Because a kilogram is a unit of mass and not weight, a one kilogram object on Earth would still be one kilogram on Jupiter. (d) The formula – GMm (1/r2-1/r1) is more/less accurate than the formula mg (r2 – r1) for the difference of potential energy between two points r2 and r1 distance away from the centre of the Earth. This site allows you to perform various gravity calculations based on Isaac Newton's law of universal gravitation. The amount of suspension force required is the mass of the internal weight (multiplied by the acceleration of gravity) minus those 0.34 newtons. The gravitational field strength of Jupiter is 27 N/kg, and the probe is 1200 kg. Problem 5. Think of it this way — time follows a simple equation: speed = distance / time. 5 / 2.2 = 2.27 kg. QUESTION/ANSWERS: Q1) How do the two methods for determining the acceleration on a body due to Earth’s gravity compare? Decide a value for the acceleration of gravity. The above formula shows that the value of acceleration due to gravity g depends on the radius of the earth at its surface. Newton's law of universal gravitation is usually stated as that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. First we must simplify the formula. It is clear from the given relation that acceleration due to gravity decreases with an increase in height. The gravitational acceleration on the sun is different from the gravitational acceleration on the earth and moon. We are giving a detailed and clear sheet on all Physics Notes that are very useful to understand the Basic Physics Concepts. ... Use the fact that acceleration due to gravity is 9.8 m/sec2 and the density of water is 1000kg/m3. [Would Humans Born On Mars Grow Taller than Earthlings?Weight is the force gravity exerts on an object due … Acceleration due to gravity (g) Gravitation Constant (G) •It is an acceleration produced on a body due to gravity •It is the force between two unit masses separated by distance of 1 m. •It is a vector quantity. About 1600, Galileo performed his famous inclined plane experiments and discovered that the acceleration of a freely-falling object is constant - that is, the object's acceleration does not change while the object is in free fall. Acceleration Due to Gravity | Definition, Formula, Units – Gravitation (d) The formula – GMm (1/r2-1/r1) is more/less accurate than the formula mg (r2 – r1) for the difference of potential energy between two points r2 and r1 distance away from the centre of the Earth. Where g is the acceleration due to the gravity of earth. 4. Similarly, you would have different values for both Jupiter and Pluto. acceleration due to gravity 5 ... 5 answers. Light (in this case, speed) is always constant and travels at a speed of 180,000 miles per second. As you can see in Figure 2, the radii of the planets vary greatly. The acceleration which is gained by an object because of gravitational force is called its acceleration due to gravity.Its SI unit is m/s 2.Acceleration due to gravity is a vector, which means it has both a magnitude and a direction.The acceleration due to gravity at the surface of Earth is represented by the letter g.It has a standard value defined as 9.80665 m/s 2 (32.1740 ft/s 2). Here are some practice questions that illustrate this concept. This acceleration is specific to Earth. To solve this example we will need to find the ratio of acceleration due to gravity of Jupiter to acceleration due to gravity of Earth. The mass of Jupiter is 1.9 × 10²⁷ and it's radius is 71 × 10⁶ and mass is 800 kg. Acceleration due to gravity is independent of the mass of the earth/ mass of the body. Solve for mass: Solve for acceleration of gravity: Solve for distance from center of mass to pivot: References - Books: Tipler, Paul A.. 1995. Every object in the universe experience gravitational force and the gravity between two objects depends upon their mass and distance. All of these values are typically known in a free fall problem except time. Escape velocity Derivation – derive formula as √(2gR) We will derive the equations using the following condition: The initial kinetic energy of the object would at least equalize the amount of work done to send the same object from the surface of the earth to an infinite distance. If gravity (and the acceleration it causes) gets weaker with distance squared, the acceleration the Moon experiences should be a lot less than for the apple. and is the acceleration due to gravity at sea level. To find the weight on Planets, we divide the weight on earth by the earth's force of gravity, which is 9.81m/s 2. Using this relationship, we can solve for the acceleration due to gravity on any planet so long as we know the planet's size. For that reason, gravity has a lesser pull on bodies of lesser mass or density than the Earth such as the moon. Gravitic acceleration = Gm/r the place G is the gravitational consistent G = 9.8 m is the mass (which might proceed to be comparable) r is the radius of earth a million.8 as a effect. Escape velocity Derivation – derive formula as √(2gR) We will derive the equations using the following condition: The initial kinetic energy of the object would at least equalize the amount of work done to send the same object from the surface of the earth to an infinite distance. Acceleration Due to Gravity Formula Questions: 1) The radius of the moon is 1.74 x 10 6 m. The mass of the moon is 7.35 x 10 22 kg. (a) Acceleration due to gravity g decreases with increasing altitude as g′=g 2 (b) Acceleration due to gravity g decreases with depth as g′=g (c) Acceleration due to gravity is, .g=GM e /R 2 e Therefore, g is independent of mass of body (d) More. Where v is final velocity; v₀ is the initial velocity; g is the acceleration due to gravity; t is total time. The acceleration that an object feels because of the force of gravity is known as gravitational acceleration. 0 energy points. Solve for acceleration of gravity: physical pendulum Solve for period. The acceleration due to gravity of Earth, for example, is known to be about 9.81 m/s² or 32.2 ft/s². Shows how to calculate the acceleration due to gravity. Acceleration due to gravity is denoted by g. Its SI unit is m/s². So if the acceleration due to gravity is directed to minus axis, it is -g. ... What is the weight of a 2.5 kg hammer on Jupiter, where the acceleration of gravity is 24.79 m/s^2 ? A Computer Science portal for geeks. We are asked to find g given the period T and the length L of a pendulum. acceleration due to this force if it is the only external force acting on the object. The weight of a 10 kg dumbell will be less on the moon. Force acting on a body due to gravity is given by, f = mg. Where f is the force acting on the body, g is the acceleration due to gravity, m is mass of the body. ). Acceleration Due to Gravity Formula Questions: 1) The radius of the moon is 1.74 x 10 6 m. The mass of the moon is 7.35 x 10 22 kg. Effective gravity on the equator is reduced by the rotation, but only by about 1/3 of a percent The bulge of the Earth's equator Assuming the Earth is exactly spherical, we expect gravity to … Physics … This acceleration is calculated to be 9.8 m/s 2. 1. Solved Examples. Newton Law of Gravity states that every particle attracts every other particle with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between them. Thus, we conclude that all objects on the Earth's surface, irrespective of their mass, accelerate straight down (i.e., towards the Earth's centre) with a constant acceleration of .This estimate for the acceleration due to gravity is slightly off the conventional value of because the Earth is actually not quite spherical.. Galileo discovered that acceleration due to gravity depended only on the mass of the object that was gravitating and not on the mass of the item pulled. A tiny bit of algebra gives a r M G e = 2. Answer questions. r = radius of planet. ... can be found in the lesson 8.02, page 2, section “Newtons’s laws” under Newton’s second law and on CK-12: “Acceleration Due to Gravity… INSTRUCTIONS: Choose the preferred units and enter the following: (M) This is the mass of the object creating the gravity. The acceleration due to gravity at the top of Mount Everest is 9.77 m/s 2. Pluto Observational Parameters Discoverer: Clyde Tombaugh Discovery Date: 18 February 1930 Distance from Earth Minimum (10 6 km) 4284.7 Maximum (10 6 km) 7528.0 Apparent diameter from Earth Maximum (seconds of arc) 0.11 Minimum (seconds of arc) 0.06 Mean values at opposition from Earth Distance from Earth (10 6 km) 5750.54 Apparent diameter (seconds of arc) 0.08 Apparent … It is maximum at poles and minimum at equator.However it is usually taken to be 9.8 m/s^2 because the variation is very little. What is the acceleration due to gravity in a region where a simple pendulum having a length 75.000 cm has a period of 1.7357 s? Calculate t in order that this infinite flat Earth has the same acceleration due to gravity on its surface as is found on the actual spherical Earth.. so if R differences to a bigger quantity, your velocity decreases whilst in comparison with the unique radius. The acceleration due to gravity at the surface of the planet = 7.35 m/s 2. gravity R - radius of the planet or object on which you calculate surf. In other words, time runs slower wherever gravity is strongest, and this is because gravity curves space-time. Example 1: The planet Mars has a mass of 6.42e23 kg and a radius (from its centre to the surface) of 3.38e6 m. a) Determine gravity on Mars. Free Fall Formula. The formula: Weight = mass x acceleration due to gravityOn Earth, acceleration due to gravity has a value of about 9.8 N/kg.On the Moon, acceleration due to gravity … Calculate the unknown variable in the equation for gravitational potential energy, where potential energy is equal to mass multiplied by gravity and height; PE = mgh. leration due to gravity of jupiter thanthat of earth. Scale drawing of the relative sizes of planets and moons in the solar system Acceleration Due to Gravity Comparison Body Mass [kg] Acceleration Due to Gravity, 'g' [m/s²] Mercury 3.18 x 1023 3.59 Venus 4.88 x 1024 8.87 Earth 5.98 x 1024 9.81 The planet Jupiter is more than 300 times as massive as Earth, so it might seem that a body on the surface of Jupiter would weigh 300 times as much as on Earth. The period T of a simple pendulum (measured in seconds) is given by the formula: T=2 π √ (L/g) (1) T = time for 30 oscillations (2) 30 oscillations using equation (1) to solve for “g”, L is the length of the pendulum (measured in meters) and g is the acceleration due to gravity … F=G*m1*M/r^2, where M is earth's mass. Its value varies from place to … We have, W = mg = 25 × 9.77 = 244.25 N The weight of the body of mass 25 kg on the top of the Mount Everest is 244.25 N. Since g is always 9.8 m/s^2, just multiply the object's mass by 9.8 and you'll get its force of gravity! If you went to another planet it would be different but on earth even if we're standing on the ground gravity is still pulling us down at a rate of 9.8 m/s/s which keeps us ffrom floating away. The formula for g from the center of the Earth to the surface is gr/R (assuming constant density, which is not really the case, but it's workable), where g = acceleration due to gravity at the surface, r = distance from the center, and R = radius of the Earth, or, if you prefer, g =-GMr/R^3. This activity is a computer lab activity in which students use Microsoft Excel to create a spreadsheet capable of calculating gravity forces and acceleration values for any two objects if the masses of the objects and their separation distance are entered. where Mand Rare the mass and radius of the planet, and G is the gravitational constant. Acceleration due to gravity on Earth is 9.8m/s^2 or for our convenience we take it 10m/s^2 . How does gravity affect objects? First, there is the variation of gravity with latitude that you alluded to: you weigh about 0.5% more at the poles than on the equator. With the 10 sets of problems in this section of the Year of the Solar System guide, students calculate weight on other planets; apply the acceleration due to gravity; calculate escape velocity and energy of a falling object; and solve other gravity-related problems.
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